JEE Main Analysis April 5 (Shift 1 & 2): I Went Through Both Shifts So You Don’t Have to Guess

I went through both shifts of the JEE Main 2026 April 5 exam in detail, looking at student reactions, expert inputs, and memory-based questions to get a clear picture of the paper. Both shifts stayed in the moderate range overall, with a similar subject-wise pattern. From the JEE Main Analysis April 5, this is what stood out to me. In Shift 1, Maths was moderate. Physics felt slightly lengthy. Chemistry was the easiest section. The 99th percentile is expected to be around 190 to 200 marks. In Shift 2, the overall level remained moderate. Maths took more time here, Physics was relatively easier than the morning shift, and Chemistry again stayed easy. The expected 99 percentile is around 180+ marks. Across both shifts, Chemistry worked as the scoring section, while Maths needed the most time. This blog on JEE Main Analysis April 5 gives a clear picture of how both shifts went. Let’s begin!

What To Expect From This Blog?

• A clear understanding of the overall difficulty level of JEE Main April 5 (both Shift 1 & 2)
• Subject-wise analysis (Maths, Physics, Chemistry) with real student reactions and trends
• Insights into which section was easiest, toughest, and most time-consuming
• A detailed look at important topics and chapter-wise weightage asked in the exam
• Memory-based questions with solutions to help you understand the question pattern
• Expected marks vs percentile trends to estimate your performance
• Key strategy takeaways like time management, question selection, and scoring approach
• Practical guidance on how to approach upcoming JEE Main shifts smartly

Check Related Articles:

• JEE Main Paper Analysis 2026 for April 2(Shift 1 and Shift 2)
• JEE Main Paper Analysis April 4 Shift 1 2026
• JEE Main Paper Analysis April 4 Shift 2

JEE Main Analysis April 5 Shift 1: What the Morning Paper Looked Like?

The Shift 1 exam was from 9 AM to 12 noon. I noticed that the overall mood when students walked out was moderate. Not a paper that shocked anyone, not one that gave easy relief either. Just a steady, well-distributed moderate exam. Some more details related to JEE Main Analysis April 5 Shift 1 have been presented below:

Subject	Difficulty Level
Mathematics	Moderate
Physics	Moderate but lengthy
Chemistry	Easy
Overall	Moderate

JEE Main Analysis April 5 Shift 1: Subject Wise Analysis

Once I looked closely at each section, a clear pattern emerged — Maths was balanced but slightly lengthy, Physics was time-consuming, and Chemistry turned out to be the scoring anchor. Here’s how each subject actually played out:

JEE Main Analysis April 5 Maths Shift 1 Analysis

From what I saw, Maths stayed comfortably in the moderate zone, but it wasn’t something you could rush through. The paper tested a wide range of topics, with a slight tilt towards Calculus and application-based questions.

• Overall difficulty remained moderate with balanced coverage
• Calculus, Vectors, and Differential Equations had noticeable weightage
• A few questions were lengthy but standard in approach
• Students with strong practice found it manageable within the time limit

Topics: Vectors & 3D, Functions, Limits, Application of Derivatives, Area under Curves, Differential Equations, Binomials, Probability, Quadratic Equations, Trigonometry, Determinants & Matrices, Conic Sections, Statistics

JEE Main Analysis April 5 Physics Shift 1 Analysis

This was the section where time pressure actually kicked in. While the concepts weren’t difficult, the length of calculations made it harder to manage within the ideal time window.

• Difficulty level was moderate but noticeably lengthy
• Questions were largely formula-based but calculation-heavy
• Many students felt this section consumed more time than expected
• Those who finished Chemistry quickly had a clear advantage here

Topics: Microscope, Elasticity, Units & Dimensions, Capacitor & Inductance, Current Electricity, Electrostatics, Magnetism, Ray Optics, Sound Wave, Semiconductors

JEE Main Analysis April 5 Chemistry Shift 1 Analysis

Chemistry turned out to be the easiest section of the paper and clearly acted as the scoring cushion for most students.

• According to JEE Main Analysis, April 5, the overall difficulty was easy and highly scoring
• The majority of students completed it in under 20–25 minutes
• Questions were mostly direct and statement-based
• JEE Main Analysis April 5 suggested that Organic Chemistry dominated, especially GOC and Biomolecules
• Inorganic Chemistry had a relatively lower weightage

JEE Main Session 2 Shift 1 Question Paper: Memory-Based Questions with Answers

These are questions students recalled after the exam from JEE Main Session 2 Shift 1 Question Paper, compiled with solutions.

JEE Main Paper Analysis: Mathematics Shift 1

Here are the Mathematics questions from the JEE Main April 5 Shift 1 paper, based on what students remembered after the exam. Let’s have a look:

• Area under Curves: The area enclosed between the region given by xy ≤ 27 & 1 ≤ y ≤ x² is — Ans: 54 ln3 – 52/3
• Functional Equation: If f(x) satisfies the relation f((x+y)/3) = (f(x)+f(y))/3 and f'(0) = 3, then the minimum value of g(x) = 3 + eˣ·f(x) is — Ans: 3(e–1)/e
• Sequence & Series: Let Sₙ = 3n²+5n be the sum of first n terms of an AP. The sum of squares of the first 10 terms of the AP is — Ans: 15220
• Probability (Tennis Match): A and B play a tennis match. The player who wins 5 rounds first wins. The number of ways A can win the match is — Ans: 126
• Complex Numbers / Quadratic Roots: If α, β are roots of ax²+bx+c=0, |α–β|=√11, α+β=3i, then the value of (α³–β³)² is — Ans: 176
• Statistics: For frequency distribution with xᵢ: 5, 6, 8, 11, 13 and fᵢ: 4, 8, 2, 3, 9 — mean deviation about mean is — Ans: 3.23
• Circles: If S₁: x²+y²–6x–8y+21=0 and S₂: x²+y²+6x+8y+λ=0, then the distance from centre of S₂ to the farthest point on S₁ is — Ans: 12
• Differential Equation + Circle: For sin(y/x)·dy/dx + 1 = (y/x)sin(y/x) with y(1)=π/2, and α = cos(y(e¹²)/e¹²), the number of integral values of p for radius r ≤ 6 in circle x²+y²–2px+2py+α+2=0 is — Ans: 11
• Matrices / System of Equations: If x–2y+tz=0, 3x+5y+t²z=0, 6x+ty+f(t)z=0 has infinitely many solutions, then y=f(t) is — Ans: Strictly increasing
• Trigonometry: If tan A and tan B are roots of x²–2x–5=0, then the value of 10 sin²((A+B)/2) is — Ans: 5 – (3/2)√10
• Vectors (3D): If r⃗×a⃗+a⃗×b⃗=0⃗, a⃗=√7î+ĵ+k̂, b⃗=ĵ–2k̂, r⃗·a⃗=0, then |3r⃗|² is — Ans: 44
• Summation (Telescoping Series): The value of Σ(n=1 to 10) [528/n(n+1)(n+2)] is — Ans: 130
• Integral Calculus: The value of ∫₀^∞ (ln x)/(x²+4) dx is — Ans: π(ln2)/4
• Probability (Bayes’ Theorem): On a postcard, either KANPUR or ANANTPUR is written. If only the letters “AN” are visible, the probability that the written word is ANANTPUR is — Ans: 10/17
• Coordinate Geometry (Equilateral Triangle): Consider equilateral △PQR where P(3,5) and QR is x+y=4. If the orthocentre of △PQR is (α,β), then 9(α+β) = — Ans: 48
• Limits: The product of all possible values of α in lim(x→0) [1–cosαx·cos(α+1)x·cos(α+2)x] / sin²(α+1)x = 2 is — Ans: –1

Section B (Numerical):

• In the expansion of (1/x³ – x⁴)ⁿ, if the sum of coefficients of x⁷ and x¹⁴ is zero, find n — Ans: 21
• The square of the distance of the point (5,6,7) from the line (x–2)/2 = (y–5)/3 = (z–2)/4 is — Ans: 6

JEE Main Analysis April 5: Chemistry Shift 1

I have listed some memory-based questions along with their answers from JEE Main 2026 Chemistry shift 1 paper. Let’s take a look:

• Chemical Kinetics (First Order): For A(g)→B(g)+C(g) with initial pressure P₀ and total pressure Pₜ at time t, the expression of rate constant K is — Ans: K = (1/t)ln[P₀/(2P₀–Pₜ)]
• Stoichiometry: On heating 2.76 g of Ag₂CO₃(s), the mass of solid residue left behind is — Ans: 2.16 g
• Solutions (Mole Fraction): Mole fraction of water in 10% w/w aqueous urea solution is — Ans: 0.967
• Thermodynamics (van’t Hoff): For reaction A ⇌ B+C with log Kp values 3.5, 2.5, 1.5 at 1/T values 0.04, 0.05, 0.06 respectively, calculate ΔH/R in Kelvin — Ans: 230
• Solubility Product: For sparingly soluble salt M₃A₂(s) with solubility x g/L and molar mass y g/mol, the value of [A³⁻]/Ksp is — Ans: (1/54)(y/x)⁴
• Chemical Kinetics (Half Life): Half life of a first order reaction is 6.93 min. Time required to complete 99% of the reaction (ln2=0.693) is — Ans: 46.06 min
• Ionic Equilibrium (pH Comparison): Three solutions A (0.1M HCl + 0.1M Ca(OH)₂), B (0.1M H₂SO₄ + 0.1M Ca(OH)₂), C (0.1M H₂SO₄ + 0.1M NaOH) — the correct pH order is — Ans: pH₃ < pH₂ < pH₁
• Hybridisation: From the list XeF₄, ICl₄⁻, ICl₂⁻, XeF₅⁻, SF₄, XeF₂, ClF₃, BrF₅, NH₄⁺ — the number of compounds with sp³d hybridisation is — Ans: 4 (ICl₂⁻, SF₄, XeF₂, ClF₃)
• Inorganic (Statement Based): Statement I: Na₂Cr₂O₇ and K₂Cr₂O₇ are used as primary standards. Statement II: Phenolphthalein is weakly basic — Ans: Both statements are incorrect
• Atomic Structure (Electronic Configuration): Correct statements from: (A) Cr has [Ar]4s¹3d⁵; (B) Size of 2pₓ < 3pᵧ; (C) Heisenberg principle applies only to electrons; (D) Energy of 2s in H = Energy of 2s in Li — Ans: A and B
• Crystal Field Theory: Statement I on eₘ destabilization 0.6Δₒ and t₂g stabilization 0.4Δₒ; Statement II on d-orbital degeneracy — Ans: Both correct
• p-Block (Nitrogen): Incorrect statements from those about N–N vs P–P bond energy, disproportionation, max covalency, d-π bond formation, and density — Ans: A, D and E
• Biomolecules (Glucose): Correct statements about glucose anomers — specific rotation of α-form is +19°, β-form has +112°, α crystallises at 307° — Ans: Statements a, b, d, e are correct

Section B (Numerical):

• In Carius method, 0.4 g organic compound gives 0.6 g BaSO₄. Find % of sulphur (nearest integer) — Ans: 21%
• Phenol reacted with dilute HNO₃. % increase in oxygen in steam volatile product with respect to phenol is ___ × 10⁻¹% — Ans: 175

JEE Main Paper Analysis Physics Shift 1

To get a list of important questions that were asked in JEE Main April 5 Shift 1 Physics, refer to the section below:

• Units & Dimensions: The dimension [ML²T⁻⁴A⁻²] represents — Ans: R/√LC
• Ray Optics (Prism): Speed of light in equilateral prism medium is 2.12×10⁸ m/s. Minimum angle of deviation is — Ans: 30°
• Wave Motion: A wave y=3sin(100t+0.018x+π/6) travels on a string. Minimum distance between two crests is — Ans: 349.06 m
• Modern Physics (Hydrogen Spectrum): Electron in hydrogen jumps from state i to f, where rᵢ/rᶠ=4/1 (minimum radii). Wavelength of emitted photon in Å (R=1.0976×10⁷ m⁻¹) — Ans: 1215 Å
• Elasticity (Young’s Modulus): If a rod’s length is doubled and area halved, what happens to Young’s modulus Y — Ans: Remains the same
• Gravitation: Points A (above) and B (below) are both 16 km from Earth’s surface (Rₑ=6400 km). Ratio gₐ/g_B = — Ans: 398/399
• Semiconductors (Logic Gates): For an LED circuit with given gate arrangement, the combination of A, B, C for both LEDs to glow — Ans: 101
• Kinematics: A ball dropped from 18 m. At the moment when magnitude of acceleration equals magnitude of velocity, its height above the ground is — Ans: 13 m
• Electromagnetism (Force on Charge): Charged particle in B⃗=(3î+2ĵ)T has acceleration a⃗=(4î–x/2 ĵ) m/s². Find x — Ans: x = 12
• Mechanics (Pulley — Tension): Pulley system with m₁=4 kg, m₂=4 kg, m₃=6 kg. Ratio T₁/T₂ = — Ans: 5/3
• Wave Optics (YDSE): In YDSE, fringe width β=2.4 mm. Setup dipped in medium of μ=1.2. New fringe width — Ans: 2 mm
• Inductors (Energy Ratio): Three equal inductors L₁=L₂=L₃ in given circuit. Ratio of total energy to energy in L₂ — Ans: 6
• Vernier Calliper: 9 MSD=10 VSD. Zero of vernier lies right of main scale zero; 7th division coincides. Zero error — Ans: +0.7 mm
• AC Circuits (RC): In RC circuit, at angular frequency ω peak current is I; at ω/4, peak current is I/3. Ratio R/Xc at ω — Ans: √(7/8)
• Compound Microscope: Objective cut into half (plano-convex). To get same magnification in normal adjustment, tube length must change by factor n — Ans: n = 2
• Moment of Inertia (Rod): MOI of uniform rod (mass m, length ℓ) about axis at ℓ/4 from centre, perpendicular to rod — Ans: 7mℓ²/48

Section B (Numerical):

• A cube (side 5 cm, modulus of rigidity 10⁵ N/m²). Top pulled by 10 N, bottom fixed. Displacement of upper surface in mm — Ans: 2 mm

JEE Mains Today Paper Analysis Shift 2: What I Found Out About The Afternoon Paper?

Shift 2 ran from 3 PM to 6 PM, and once students started coming out, reactions were similar, moderate overall, with Maths being the heaviest again. One thing consistent across both shifts today: anyone who made good time in Chemistry had a real advantage going into Maths. To get more important details related to JEE Main Analysis April 5, you can refer to the table below:

Subject	Difficulty Level
Mathematics	Moderate & Lengthy
Physics	Easy to Moderate
Chemistry	Easy
Overall	Moderate

JEE Main Paper Analysis April 5 Shift 2: How I Saw Shift 2 Play Out Across Subjects?

After going through the JEE Main Analysis of the afternoon paper, the pattern stayed quite similar to the morning. But there was one key difference: Physics felt lighter, while Maths continued to demand the most time. Chemistry, once again, gave students the breathing space they needed.

Maths Shift 2

From what I observed, Maths leaned slightly heavier than Shift 1 in terms of time required. The weightage clearly shifted towards Calculus and Coordinate Geometry, and a few problems were long enough to slow students down significantly.

• Difficulty level stayed moderate, but more time-consuming
• Calculus and Coordinate Geometry dominated the paper
• Some questions required 5–7 minutes individually
• Differential Equations appeared again, making it a repeat high-weight topic
• Overall, accuracy + question selection became crucial here

Topics: Coordinate Geometry, Calculus, Differential Equations, Sequence and Series, Binomials, Probability, Vectors & 3D, Area Under the Curve

Physics Shift 2

I found out through JEE Main Analysis April 5 that Physics felt more manageable in this shift. Most questions followed standard patterns and didn’t require lengthy calculations.

• Difficulty level was easy to moderate
• Questions were largely formula-based and direct
• Included more standard textbook applications
• Several statement-based questions focused on theory clarity
• Overall, it was a scoring section for most students

Topics: Moment of Inertia, Rotation, De Broglie’s Wavelength, Electrostatics, Current, Ray Optics, Units & Dimensions, Thermodynamics

Chemistry Shift 2

As per JEE Main Analysis April 5 Chemistry in Shift 2 had broader coverage compared to Shift 1, touching all three major branches — but the nature of questions remained straightforward.

• Difficulty level remained easy and highly scoring
• Covered Physical, Organic, and Inorganic Chemistry
• Questions were mostly NCERT-based and direct
• Many required little to no calculation
• Helped students save time for Maths

Topics: Biomolecules, GOC, IUPAC Naming, Ionic Equilibrium, Conductivity, Chemical Kinetics, Mole Concept, Liquid Solutions, Coordination Compounds, Salt Analysis

JEE Mains Session 2 Question Paper April 5 Shift 2: Memory-Based Questions with Answers 

After going through the JEE Main Analysis April 5 , I compiled these memory-based questions from what students recalled after the exam. This should give you a fair idea of the level, the type of questions asked across all subjects.

JEE Main Analysis April 5 Mathematics Shift 2

JEE Main Session 2 2026 April 5 Mathematics Shift 2 questions have been presented below:

• Permutation & Combination: A bag has 5 red, 6 blue, 4 black balls. The number of ways 8 balls can be selected with at least 2 of each colour is — Ans: 4100
• Coordinate Geometry (Parabola): For parabola y²=8x, the directrix cuts x-axis at A, PQ is a focal chord with slope of PA=3/5 and abscissa of P > 1. Area of △AQP = — Ans: 80/3
• Arithmetic Progression: Let A₁, A₂, …, A₄₉ be 49 AMs between 49 and 149. The mean of A₁, A₂₅, A₄₇, A₄₉ is — Ans: 110
• Functions + Integral: If 3ᵃ+3⁻ᵃ, f(a) and 2¹⁺ᵃ+2¹⁻ᵃ are in AP and α is the minimum value of f(x), then ∫[ln(α–1) to lnα] dx/(e²ˣ–e⁻²ˣ) is — Ans: (1/2)ln(4/3)
• Vectors: Let OP⃗=a⃗, OQ⃗=b⃗. R on OP with 5OR⃗=OP⃗, and M on OQ with 5RM⃗=OQ⃗. Then PM⃗ = — Ans: (b⃗–4a⃗)/5
• Trigonometry (Set): If S={θ: θ∈[–π,π], cosθ·cos(5θ/2)=cos7θ·cos(7θ/2)}, then n(S) = — Ans: 19
• Probability (Total Probability): P(A chosen as captain)=0.6, P(B)=0.4. If A is captain, P(win)=0.8; if B, P(win)=0.7. Total P(win) = — Ans: 0.76
• Differential Equation: For √tanx dy = (sec³x – y·(tanx)^(3/2))dx with y(π/4) = 6√2/5, the value of y(π/3) is — Ans: (8/5)·3^(1/4)
• Complex Numbers: If Z₁, Z₂ are roots of Z²+4Z–(1+12i)=0, then |Z₁|²+|Z₂|² = — Ans: 34
• Limits (Point of Intersection): Let f(x) = lim(y→0)[(1–cos(xy))tan(xy)/y³]. Number of intersection points of f(x) = sinx is — Ans: 3
• Integral Equation: If f(x) satisfies f(x) = ∫₁ˣ f(t)dt + (1–x)(logₑx–1)+e, then f(f(1)) = — Ans: 1+eᵉ
• GP + Quadratic: α,β are roots of x²–4x+p=0; γ,δ are roots of x²–x+q=0. When α,β,γ,δ form a GP with positive common ratio, (p+q) = — Ans: 34/9
• Coordinate Geometry (Reflection of Lines): Line L: x+y=0. Lines L₁, L₂ through (–1,–1) at 45° from L. Their reflections in 2y+x=1 are ax+by=9 and cx+dy=1. Then |ad+bc| = — Ans: 1
• Binomial Theorem: Coefficient of x² in (2x²+1/x)¹⁰ is — Ans: 3360
• Series Sum: Sum of first 10 terms of 1/(1+4·1⁴) + 2/(1+4·2⁴) + 3/(1+4·3⁴) + … = m/n (coprime). Then m+n = — Ans: 276
• Hyperbola: Foci at (3,5) and (3,–4). Eccentricity satisfies 3e²–11e+6=0. Length of latus rectum — Ans: 24
• Set Theory (Relations): If A={2,3}, B={5,6}, number of relations from A×B to A×B is — Ans: 2¹⁶
• Coordinate Geometry (Distance): Distance of point (a,2,5) from image of (1,2,7) in line x/1=(y–1)/1=(z–2)/2 is 4. Sum of all possible values of a — Ans: 6

Section B (Numerical):

• Let f(n) be a 3×3 determinant with entries as given. If Σ(n=1 to k) f(n)=98, find k — Ans: 3
• 3rd order matrix M with given column vectors: if M[x,y,z]ᵀ=[2,4,7]ᵀ, then x+y+z = — Ans: 3
• A={1,4,7}, B={2,3,8}. Relation R on A×B defined by (a₂+b₁)|(a₁+b₂). Number of relations — Ans: 18

JEE Main Analysis April 5 Chemistry Shift 2

Chapter-wise chemistry questions that were asked in JEE Main April 5 Chemistry Shift 2 have been shared below:

• Colligative Properties (Osmotic Pressure): 20 g of haemoglobin in 1 L at 300 K, height difference 80 mm through SPM (density=1000 kg/m³, g=10 m/s²). Molar mass in kg/mol — Ans: 62 kg/mol
• Equilibrium (KP Expression): For A(g) ⇌ B(g)+C(g), initial moles a, x moles decompose at total pressure P. Value of KP = — Ans: x²P/(a²–x²)
• Molar Heat Capacity: Order of molar heat capacity (Cₘ) of Br₂(l), Cu(s) and He(g) at 298 K and 1 atm — Ans: Br₂(l) > Cu(s) > He(g)
• Stoichiometry / Gas Laws: 20 g Zn treated with 50 mL of 50% w/w H₂SO₄ (d=1.3 g/mL). Volume of H₂ gas at STP is — Ans: 6.81 L
• Kinetics (Half Life Graph): For A→Product, a t₁/₂ vs [A₀] graph is linear. Given t₁/₂=120 sec at [A₀]=4×10⁻³ M. Find x at [A₀]=1.5×10⁻³ M — Ans: x = 45 sec
• Thermodynamics (Gibbs Energy): For X₂(g)+Y₂(g) ⇌ 2XY(g) at 600K, using the given ΔfH and Sm° table, calculate ΔᵣG — Ans: –10 kJ/mol
• Electrochemistry (Nernst): Silver rod in unknown AgNO₃, Zn rod in 1M ZnSO₄. EMF=1.6V. Find log₁₀[Ag⁺] — Ans: 4/5.9
• Conductometry: Molar conductivity=123.5 Scm²/mol, conductance=0.19 S, cell constant=1.3, density=1 g/mL, molar mass=75 g/mol. Concentration x% w/w — Ans: 15%
• Coordination Chemistry (CFT / Unpaired Electrons): For d³, d⁴(low spin), d⁵(high spin), d⁷(low spin), d⁶(high spin) complex ions, total unpaired electrons — Ans: 15
• d-Block / Inorganic: Species X dissolved in H₂SO₄ reacts with SO₂ to give green solution. X is — Ans: K₂Cr₂O₇
• Orbital Energy Comparison: For multi-electron species, energy order of orbitals: (A) n=3,ℓ=0; (B) n=3,ℓ=1; (C) n=4,ℓ=2; (D) n=3,ℓ=2 — Ans: C > D > B > A
• Oxide Nature (Statement Based): Statement I: [Al₂O₃, Cr₂O₃], [CO, N₂O], [Na₂O, V₂O₃], [Cl₂O₇, Mn₂O₇] — 4 sets with same oxide nature. Statement II: most basic is Na₂O, most acidic is Cl₂O₇ — Ans: Both correct
• Organic (Benzyl Isocyanide): Which of the following give benzyl isocyanide as major product — PhCH₂NH₂+CHCl₃/NaOH and PhCH₂Br+AgCN — Ans: (i) and (ii)
• Biomolecules (Glucose): Statement I on α and β-D-Glucose anomers. Statement II on identical configuration at C-3, C-4, C-5 in glucose and fructose — Ans: Both correct

Section B (Numerical):

• Grignard reagent RMgX + H₂O → gas X (volume 1.4 dm³/g at STP). X + I₂ → Y. Y + Na/dry ether → Z. Find molecular mass of Z — Ans: 30

JEE Main Analysis April 5 Physics Shift 2

For JEE Main April 5 Physics Shift 2 Questions, refer to the section below:

• Calorimetry: x g of water at 50°C cools to 0°C releasing heat H. If (100–x) g at 50°C is completely vaporised also requiring heat H, find x — Ans: 92.18 g
• Work Done by Friction: A 1 kg block on 30° inclined plane given initial velocity 4 m/s upward (friction sufficient, no sliding). Work done by friction in 2 sec — Ans: 20 J
• Rotational Motion: Wheel from rest under uniform angular acceleration. Rotates θ₁ in first 2 sec, θ₂ in next 2 sec. Ratio θ₂/θ₁ = — Ans: 3
• Electromagnetic Induction: Metallic ring (radius 20 cm, R=2Ω) in field B=(2t²+2t+3)T perpendicular to its plane. Induced current at t=2 sec (π=22/7) — Ans: 0.63 A
• De Broglie Wavelength: Electron enters medium where velocity reduces by 20%. De Broglie wavelength in medium = α·λ₀. Value of α — Ans: 1.25
• Wave Optics (YDSE): Slit separation d=5λ, screen at D=10d. Maximum intensity is I₀. Intensity directly in front of one slit — Ans: I₀/2
• Rolling Motion: A rolling object reaches maximum height 7V₀²/10g. The object is — Ans: Solid sphere
• Ray Optics (Two Lenses): Object 15 cm from lens 1 (f=10 cm). Lens 2 (f=15 cm) is 15 cm from lens 1. Distance of final image from lens 2 — Ans: 7.5 cm
• Measurement (Error): Voltage = (20±0.2) V, current = (10±0.1) A. Maximum error in resistance — Ans: 0.04 Ω
• Semiconductors (PN Junction): P side highly doped, N side lightly doped. Depletion layer extends more in — Ans: N side
• AC Circuits (Resonance): RLC circuit with R=50Ω, L=1.6 H, C=40μF. Inductive reactance at resonance — Ans: 200 Ω
• Elasticity: Rod of volume V and Young’s modulus Y subjected to stress τ. Elastic energy stored — Ans: τ²V/(2Y)
• Gravitation (Escape Velocity): Planet has half Earth’s radius, same density. Escape speed from that planet is Vₑ/N. Find N — Ans: N = 2
• Surface Tension: 8 small liquid drops of radius r and surface tension T combine into one. Change in surface potential energy — Ans: 16πr²T
• Current Electricity (EMF): EMF source with internal resistance r: when R=5Ω, i=1A; when R=2Ω, i=2A. Find r — Ans: 1 Ω
• Nuclear Physics: Binding energy of ¹²C with mₚ=1.0078u, mₙ=1.0087u — Ans: 92.19 MeV

Section B (Numerical):

• In YDSE with slit separation d, screen at D, maximum intensity I₀. Intensity at a specific point involving path difference from field B=B₀e⁻ˣ on metallic rod (length L, angular velocity ω). Induced EMF between ends — Ans: B₀ω(1–e⁻ᴸ(1+L))/λ²

JEE Mains Marks vs Percentile: What Your Score Could Mean?

Based on past trends and NTA’s normalisation formula:

Raw Score (Out of 300)	Expected Percentile
290 – 300	99.997 – 100
250 – 260	99.95 – 99.97
220 – 230	99.80 – 99.86
190 – 200	99.48 – 99.62
180 – 190	99.29 – 99.48
160 – 170	98.77 – 99.06
130 – 140	97.35 – 97.94
100 – 110	95.64 – 96.20
90 – 100	94.39 – 94.99
70 – 80	90.41 – 91.07
50 – 60	81.57 – 82.01

A Quick Note for Students Appearing in Remaining JEE Mains Shifts: My Suggestions

Based on what April 5 showed, a few clear patterns are emerging. If you still have your exam coming up, this is what you should keep in mind:

• Maths is taking the most time
  • Consistently, the lengthiest section across shifts
  • High-weight topics include Calculus, Coordinate Geometry, Vectors & 3D, Differential Equations, and Binomials
  • Avoid spending too long on a single question, move on if stuck
• Chemistry is the scoring section
  • Least time-consuming among all three subjects
  • Strong focus on NCERT-based topics
  • Repeated areas include Biomolecules, GOC, Coordination Compounds, and Chemical Kinetics
• Physics is moderate but calculation-driven
  • Mostly formula-based questions
  • Key areas include Mechanics, Electromagnetism, and Modern Physics
  • Statement-based questions need careful reading, and avoid rushing
• Syllabus weightage trend
  • Around 60:40 split in favour of Class 12 topics
  • Overall syllabus coverage still remains balanced

Conclusion

After going through both shifts, one thing is clear to me. The paper was not about difficult concepts, it was more about time management and smart selection. Maths needed patience, Physics needed steady focus, and Chemistry gave the scoring edge. Both shifts stayed moderate, but small differences in time pressure made the real impact. If I had to sum up the JEE Main Paper Analysis April 5, it comes down to staying calm, using Chemistry to save time, and not getting stuck in Maths.